If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X^2+6X-1599=0
a = 1; b = 6; c = -1599;
Δ = b2-4ac
Δ = 62-4·1·(-1599)
Δ = 6432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6432}=\sqrt{16*402}=\sqrt{16}*\sqrt{402}=4\sqrt{402}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-4\sqrt{402}}{2*1}=\frac{-6-4\sqrt{402}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+4\sqrt{402}}{2*1}=\frac{-6+4\sqrt{402}}{2} $
| A=-5n-6 | | y–8.1=4.3-2y+8 | | r−58/6=4 | | 2(q+18)=96 | | 5x-14+7x-4x-16=3x-8+6x-2+3 | | 8=v+47/8 | | s+10/3=7 | | d/8+84=90 | | y=5(2)^8 | | 0=−16t^2+300 | | y=5(4)^4 | | y=1250(0.865)^(3) | | -1-3-4-(3-x)=27 | | -x^2+490x=0 | | 3.7x-2.4=2,9x+1.2 | | 2000Q-0.02(x^2)=0 | | -x^2+490=0 | | 40+15+0.25x=40+0.35x | | y=475(0.5)^(3) | | 5.4=(6.4)x | | 3.5x+5=4 | | 5.4=6.4x | | x+14+8+14=180 | | y=28000(.9)^10 | | (3x-7)(4)=0 | | y=62(.95)^3 | | 5+x−1=x+6 | | 64+r=87 | | y=60(1.05)^3 | | 2/5x-1/2=3/4x+5 | | 5x^2-18x+90=0 | | 9(2+b)=54 |